A rectangular sandbox has a width of 555 feet. The sandbox is 555 times as long as it is wide. What is the perimeter of the sandbox?
Answers
Answered by
4
Perimeter of rectangle=2(l+b)
b=555 ft
l=555*b
=555*555=308025
Perimeter=2(308025+555)
=2*308580
=617160 ft
b=555 ft
l=555*b
=555*555=308025
Perimeter=2(308025+555)
=2*308580
=617160 ft
Answered by
4
width of the sand box = b=555ft
length = l= 555b
= 555*555
=308025ft
perimeter of the box= 2(l+b)
= 2(308025+555)
=2*308580
=617160ft
length = l= 555b
= 555*555
=308025ft
perimeter of the box= 2(l+b)
= 2(308025+555)
=2*308580
=617160ft
mysticd:
u'r welcome
Similar questions