Question

a rectangular section of b/d ratio 0.5 and a area of circular cross section 10,000mm2.The ratio of moment of resistance of rectangular to that circular is

Answer 1

Given, Length of the room = 15 m

Width of the carpet = 75 cm =   ( 1m = 100 cm)

Let the length of the carpet required for carpeting the room be x m.

Given, Cost of carpet = Rs 80/ m

Cost of x m carpet = Rs  × x m = Rs 80x m 

Given, Cost of carpeting the room = Rs 19200

∴ 80 x = 19200

⇒ x = 240.

So, the length of carpet required for carpeting the room is 240 m.

Area of carpet required for carpeting the room 

= Width of the carpet × Length of the carpet



= 180 m2

Let the width of room be  b m.

Area to be carpeted in the room = 15 m × bm = 15 b m2

∴ 15b m2 = 180 m2



Thus, the width is room is 12 m.

Cheers!