Question

. A rectangular sheet of
44 cm x 14 cm is rolled along its length and a cylinder
is formed. Find the surface area of the cylinder.​

Answer 1

Answer:

We are given a rectangular sheet of paper of dimensions 44 cm* 14 cm is rolled along its length

So, height of formed cylinder = Length of rectangular sheet = 14 cm

Circumference of base of cylinder = Breadth = 44 cm

Circumference of circle = 2\pi r2πr

So, 2\times \frac{22}{7} \times r = 442×

7

22

×r=44

r = \frac{44\times 7}{2\times22}r=

2×22

44×7

r = 7r=7

Radius of cylinder is 7 cm

Height = 14 cm

Total surface area of cylinder = 2\pi r (h+r)2πr(h+r)

= 2 \times \frac{22}{7} \times 7 (14+7)2×

7

22

×7(14+7)

= 924 cm^2924cm

2

Hence the total surface area of cylinder formed is 924 cm^2924cm

2