A rectangular sheet of aluminium foil is 44 cm long and 22 cm wide a cylinder is made out by rolling the foil along its length find the total surface area of the cylinder
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Length of rectangular sheet = Height of cylindrical sheet h
So, Height​ of cylindrical sheet =44cm
According to question=>
Area of rectangular sheet = Lateral surface area of cylindrical sheet
So, l*b = 2*pi*r*h
44 *22 = 2 * 3.14 * r* 44
968 = 276.32* r
r = 968/276.32
r = 3.50
So, T. S. A. of cylindrical sheet = 2*pi*r(r+h)
=2*3.14*3.50(3.50+44)
= 21.98*47.5
= 1044.05 cm^2
3.0
So, Height​ of cylindrical sheet =44cm
According to question=>
Area of rectangular sheet = Lateral surface area of cylindrical sheet
So, l*b = 2*pi*r*h
44 *22 = 2 * 3.14 * r* 44
968 = 276.32* r
r = 968/276.32
r = 3.50
So, T. S. A. of cylindrical sheet = 2*pi*r(r+h)
=2*3.14*3.50(3.50+44)
= 21.98*47.5
= 1044.05 cm^2
3.0
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