Question

a rectangular sheet of aluminium foil is 44cm multiply 20cm is folded to make a cylinder of height 20 cm find the volume of the cylinder assuming there is no overlapping of paper

Answer 1

Answer:

3080 Cm^3

Step-by-step explanation:

Let the dimensions of the rectangular sheet,

Length = a = 20 Cm

Breadth = b = 44 Cm

Also, Let the Radius if the cylinder be r and Height of the cylinder be h

No, according to Question,

Height of the cylinder = Length of the rectangular sheet

Thus, h = a = 20 Cm

Also, since the sheet is folded without overlapping.

Thus, Circumference of the bottom of the cylinder = Breadth = 44 Cm

So,      2 * pi * r = 44

          2 * 22/7 * r = 44

              r  =  7 Cm

So, now

According to the formula of the cylinder

Volume of the cylinder  =  pi * r^2 * h

                                       =  22/ 7 * 49 * 20

                                       = 440 * 7

                                        =  3080 Cm^3

Answer 2

Suar ki bajhi bhen ki ----

Step-by-step explanation: