a rectangular sheet of aluminium foil is 44cm multiply 20cm is folded to make a cylinder of height 20 cm find the volume of the cylinder assuming there is no overlapping of paper
Answers
Answer:
3080 Cm^3
Step-by-step explanation:
Let the dimensions of the rectangular sheet,
Length = a = 20 Cm
Breadth = b = 44 Cm
Also, Let the Radius if the cylinder be r and Height of the cylinder be h
No, according to Question,
Height of the cylinder = Length of the rectangular sheet
Thus, h = a = 20 Cm
Also, since the sheet is folded without overlapping.
Thus, Circumference of the bottom of the cylinder = Breadth = 44 Cm
So, 2 * pi * r = 44
2 * 22/7 * r = 44
r = 7 Cm
So, now
According to the formula of the cylinder
Volume of the cylinder = pi * r^2 * h
= 22/ 7 * 49 * 20
= 440 * 7
= 3080 Cm^3
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Step-by-step explanation: