A rectangular sheet of cardboard is 4cm by 2cm. The greatest possible circle is cut off from the cardboard, then find the remaining area.
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Dimensions of the cardboard=4 cm and 2 cm
Area of the cardboard= 2 cm*4 cm=8 cm²
Since the least dimension= 2 cm,
the greatest possible circle can have a diameter of maximum 2 cm.
Radius=D/2=1 cm.
Area of the circle=πR²
=22/7*1*1 cm²
=22/7 cm²
Remaining area=8 cm² - 22/7 cm²
=34/7 cm² =4 6/7 cm²(Mixed fraction)
Ans:The remaining area is 4 6/7 cm².
Area of the cardboard= 2 cm*4 cm=8 cm²
Since the least dimension= 2 cm,
the greatest possible circle can have a diameter of maximum 2 cm.
Radius=D/2=1 cm.
Area of the circle=πR²
=22/7*1*1 cm²
=22/7 cm²
Remaining area=8 cm² - 22/7 cm²
=34/7 cm² =4 6/7 cm²(Mixed fraction)
Ans:The remaining area is 4 6/7 cm².
shanmu54321:
Thanks alot
ur class?
9th
oh!!!! how can it be!!! i'm in 7 th class yet i have ansered this one and u can't!!!!!!!
Answered by
2
Step-by-step explanation:
Total area of card board =8cm
radius= 2/2
=1
area of a circle =π r²
=π×(1)²
=π
remaining area =(8-π)sq cm
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