Math, asked by subhi4414, 11 months ago

A rectangular sheet of length 132cm and breadth 21cm is folded to form a cylinder. Find the total surface area of the cylinder so obtained.

Answers

Answered by amankaul
4

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Answered by GulabLachman
2

The total surface area of the cylinder so obtained is 2842.19 cm², when the rectangular sheet is folded along breadth.

Given,

length of sheet = 132cm,

breadth = 21cm.

When this rectangular sheet is folded along its breadth to a cylinder, it would be a hollow tube with two open ends.

The ends of the tube would have circumference equal to the breadth of sheet = 21cm.

Let the radius of the tube be 'r' cm.

So, 2Пr = 21                                        [Circumference = 2Пr]

r = 21/2П

The total surface area is given as:

SA = 2Пr(r+h), where h is the height = length of sheet = 132 cm

So, SA = 2П(21/2П)[ (21/2П + 132]

            = 2П(21/2П)[135.34]

            = 2842.19 cm²

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