A rectangular sheet of metal 44cm long and 20 cm broad is rolled along its length into a right circular cylinder so that the cylinder has 20cm as it's height. Find the volume and curved surface area of the cylinder so formed.
Answers
Answered by
91
if a rectangular sheet is folded along its length into a cylinder then it's length will be circumference base of cylinder.
2 πr = 44cm
2 ×22 / 7 ×r = 44cm
r = 7cm
h = 20cm
volume of cylinder = π R^2h
= 22 / 7 ×7 ×7 ×20 cubic cm
=3,080 cubic cm
curved surface area of cylinder =2 πrh
= 2 ×22 / 7 ×7 ×20 square cm
= 880 square cm
2 πr = 44cm
2 ×22 / 7 ×r = 44cm
r = 7cm
h = 20cm
volume of cylinder = π R^2h
= 22 / 7 ×7 ×7 ×20 cubic cm
=3,080 cubic cm
curved surface area of cylinder =2 πrh
= 2 ×22 / 7 ×7 ×20 square cm
= 880 square cm
Answered by
39
Thank you for asking this question. Here is your answer:
We know that the length of the rectangular sheet L = 44 cm
and the breadth of the rectangular sheet B =20 cm
The radius r of the cylinder=circumference of the base of cylinder
=
44=2x22/7r
44x7/44
r=7
and the height h of the cylinder =20cm
volume of cylinder will be π²h
V=22/7x7x7x20
V=22x7x20
V=3080cm³
If there is any confusion please leave a comment below.
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