Question

a rectangular sheet of metal foil with dimension 66 cm by 12 cm is rolled to form a cylinder of height 12 cm. Find the volume of cylinder.

Answer 1

hey there...

here is ur answer...

the formula for the volume of a cylinder is

πr^2h

pie * radius * radius * height

so now, we know the values of pie, height.

we have to find the value of the radius

the length of the rectangle is 66cm and cylinder has two circles ... so the length if the rectangle is twisted to form the circumference of the circles .. one of the circles.

so,

2πr = 66

r = 66/2π

$\frac{66}{ \frac{22}{7} \times 2 }$

$\frac{33}{ \frac{22}{7} }$

$33 \times \frac{7}{22}$

$3 \times \frac{7}{2}$

$\frac{21}{2}$

r = 10.5 CM

the volume will be

$\frac{22}{7} \times 10.5 \times 10.5 \times 12$

= 29106/7

=
$4158 {cm}^{3}$

hope this helps!