Question

A rectangular sheet of metal is 40cm by 15cm. Equal squares of side 5cm are cut off at the corners and the remainder is folded up to form an open rectangular box. The volume of the box is:

Answer 1

Answer:

Answer –

A.750cm

3

Explanation :

Length of rectangular sheet = 40 cm

Breadth of rectangular sheet = 15 cm

Since, squares of side 5 cm are cut off from the corner of the sheet.

Therefore, new length = 40 – (5 + 5) cm = 30 cm

new breadth = 15 – (5 + 5) cm = 5 cm

Now, volume of the open box = (30 × 5 × 5) cm

3

 = 750 cm

3

Answer 2

Correct Question:-

A rectangular sheet of metal is 40cm by 15cm. Equal squares of side 5cm are cut off at the corners and the remainder is folded up to form an open rectangular box. Then what is the volume of the box ?

Required Answer:-

Given:-

$\\\sf{\rightarrow{Length \:of\:the\:rectangular\:sheet\:is\:40cm}}$

$\sf{\rightarrow{Breadth\:of\:the\:rectangular\:sheet\:is\:15cm}}$

$\sf{\rightarrow{Height\:of\:the\:box\:is\:5cm}}$

$\sf{\rightarrow{Equal\:squares\:of\:5cm\:sides\:are\:cut\:off}}$

To Find:-

$\\\sf{\rightarrow{Volume\:of\:the\:box}}$

Solution:-

As, equal squares of side 5cm are cut off from the corners;

Therefore,

$\\\sf{New \: length \: of \: the \: box = \bold{(40 - 5 \times 2)cm}}\\\therefore{\sf{New\: length \: of \: the \: box = \bold{30cm}}}$

Again,

$\\\sf{New\: breadth \: of \: the \: box = \bold{(15 - 5 \times 2)}}cm\\\therefore{\sf{New\: breadth \: of \: the \: box = \bold{5cm}}}$

Now, we know that:-

$\\\boxed{\rm{\blue{\bold{Volume} = length \times breadth \times height }}}$

According to the question:

$\\\sf{\bold{Volume} = 30cm \times 5cm \times 5cm}$

$\\\sf{\implies{\bold{Volume} = (30 \times 5 \times 5) {cm}^{3} }}$

$\\\sf{\therefore{\red{\bold{Volume} = 750 {cm}^{3} }}}$

$\\\underline{\boxed{\rm{\green{Hence,\:volume\:of\:the\:box\:is\:\bold{750 {cm}^{3}}}}}}$