A rectangular sheet of metal of area 440 sq.Cm is folded in a cylinder to enclose a volume of 1540
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Given That:
Area of Rectangle = 440 sq cm
Volume of Cylinder = 1540 cu cm
Solution:
Since the rectangular metal sheet is folded to form a cylinder, then the Area of Rectangle must be equal to the Lateral Surface Area of the Cylinder.
Therefore, Lateral Surface Area of Cylinder = 2π x r x h = 440 ..........E1
or rh = 70
Also Volume of Cylinder = π x r^2 x h = 1540
or π x rh x r = 1540
or π x 70 x r = 1540
Therefore, r = 7
Now, substituting the value of r in E1, we get
2π x 7 x h = 440
Therefore, h = 10
Hence, the dimensions of the cylinder formed are Radius = 7 cm & Height = 10 cm
Hope your question completes here
Area of Rectangle = 440 sq cm
Volume of Cylinder = 1540 cu cm
Solution:
Since the rectangular metal sheet is folded to form a cylinder, then the Area of Rectangle must be equal to the Lateral Surface Area of the Cylinder.
Therefore, Lateral Surface Area of Cylinder = 2π x r x h = 440 ..........E1
or rh = 70
Also Volume of Cylinder = π x r^2 x h = 1540
or π x rh x r = 1540
or π x 70 x r = 1540
Therefore, r = 7
Now, substituting the value of r in E1, we get
2π x 7 x h = 440
Therefore, h = 10
Hence, the dimensions of the cylinder formed are Radius = 7 cm & Height = 10 cm
Hope your question completes here
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