A rectangular sheet of paper 30 cm into 18 cm can be transformed into the curved surface of a right circular cylinder interviews namely either by Rolling the paper along its length or ride along its base find the ratio of its volume of the two cylinders thus formed
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Answer:
5:3
Step-by-step explanation:
Given dimensions are 30cm * 18cm.
(i)
Let v₁ be the volume of cylinder which is formed by rolling the sheet along its length.
Given, height(h₁) = 18 cm.
We know that circumference of base of cylinder = 2πr₁ = 30
⇒ πr₁ = 15
⇒ r₁ = 15/π
We know that volume of cylinder(v₁) = πr²h
⇒ πr₁²h₁
⇒ π(15/π)(15/π) * 18
⇒ (4050/π) cm³
(ii)
Let v₂ be the volume of cylinder which is formed by rolling the sheet along its width.
Given, height(h₂) = 30 cm.
We know that circumference = (2πr₂)
⇒ 2πr₂ = 18
⇒ πr₂ = 9
⇒ r₂ = (9/π)
We know that volume of cylinder(v₂) = πr²h
⇒ πr₂²h₂
⇒ π(9/π)(9/π)*(30)
⇒ (2430/π) cm³
Now,
v₁ : v₂
⇒ (4050/π) : (2430/π)
⇒ 4050:2430
⇒ 5:3.
Therefore, ratio of volume of the volume of two cylinders formed = 5:3
Hope it helps!
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