Question

A rectangular sheet of paper is 1/12 cm long and 2/10cm wide. Find its perimeter.​

Answer 1

Answer:

perimeter of rectangle is 2 (l+b)

2 (1/12+2/10)

2 (5+12/60)

2 (17/60)

2×17/60=17/30

17/30 is the answer to this question

Answer 2

Given:

→ Rectangular sheet having a Length of 1/12 cm and 2/10 cm Breadth.

To find:

→ The perimeter of the rectangular sheet of paper.

Solution:

Perimeter of the rectangular sheet of paper = 2 ( l + b )

= 2 ( 1/12 + 2/10 )

LCM of 12 and 10

2 | 12,10

2 | 6,5

5 | 3,5

3 | 3,1

1 | 1,1

LCM (12,10) = 2² * 5 * 3

= 2 ( 1/12 + 2/10)

First,

1/12

Multiplying numerator and denominator with 5

5*1 / 5*12

5 / 60

Second,

2/10

Multiplying numerator and denominator with 6

2*6 / 10*6

12/60

Now,

= 2 ( 5/60 + 12/60 )

= 2 ( 17/60 )

= 2 * 17/60

= 17/30

Conclusion:

Therefore, 17/30cm is the perimeter of the rectangular sheet of paper.

Verification:

2 (l + b) = Perimeter of the rectangular sheet of paper

2 ( 1/12 + 2/10 ) = 17/30

LCM of denominators

2 ( 5/60 + 12/60 ) = 17/30

2 ( 17/60 ) = 17/30

2 * 17/60 = 17/30

17/30 = 17/30

LHS = RHS

Hence, verified.

Extra Information:

Perimeter of a rectangle = 2 ( Length * Breadth )

Area of a rectangle = lb