Question

A rectangular sheet of paper is 12 1/2 cm. long 10 2/3 cm. wide. its perimeter is​

Answer 1

➣ AnSwer :-

$\longrightarrow \sf \:2 \times (12 \frac{1}{2} + 10 \frac{2}{3})$

$\longrightarrow \sf \:2 \times ( \frac{25}{2} + \frac{32}{3} )$

LCM of 2 and 3 is 6.

$\longrightarrow \sf \:2 \times ( \frac{25 \times 3}{2 \times 3} + \frac{32 \times 2}{3 \times 2} )$

$\longrightarrow \sf \:2 \times ( \frac{75}{6} + \frac{64}{6} ) = 2 \times ( \frac{75 + 64}{6} )$

$\longrightarrow \sf \frac{139}{6} = 23 \frac{1}{6}$

Therefore,the perimeter of the rectangle is 23 1/6 cm.

Answer 2

$\huge\mathbb { \red{ \underline{Solution}}}$

$2 \times ( 12\frac{1}{2} + 10\frac{2}{3} )$

$2 \times ( \frac{25}{2} + \frac{32}{3} )$

• LCM of 2 and 3 is 6

$2 \times ( \frac{25 \times 3}{2 \times 3} + \frac{32 \times 2}{3 \times 2} )$

$2 \times ( \frac{75}{6} + \frac{64}{6} )$

$2 \times ( \frac{75 + 64}{6} )$

$\frac{139}{6} = 23 \frac{1}{6}$