Question

a rectangular sheet of paper is 12 integer 1 upon 2 cmm long and 10 integer 2 upon 3 cm wide find it's perimeter​

Answer 1

Step-by-step explanation:

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Answer 2

As per the provided information in the given question, we have:

• Length of rectangular sheet is 12½ cm.
• Width of rectangular sheet is 10⅔ cm.

We've been asked to calculate the perimeter of the rectangle.

¤ Perimeter of rectangle is twice the sum of it's length and width. $\\\longrightarrow\sf{{Perimeter}_{(Rectangle)}=2(length+width)}$

Substituting value of length as 12½ cm and width as 10⅔ cm.

$\longrightarrow\sf{{Perimeter}_{(Rectangle)}=2\left(12\dfrac{1}{2}+10\dfrac{2}{3}\right)}$

$\longrightarrow\sf{{Perimeter}_{(Rectangle)}=2\left(\dfrac{25}{2}+\dfrac{32}{3}\right)}$

Adding 25/2 and 32/3, $\\\longrightarrow\sf{{Perimeter}_{(Rectangle)}=2\left(\dfrac{25\times 3+32\times 3}{3\times 2}\right)}$

$\longrightarrow\sf{{Perimeter}_{(Rectangle)}=2\left(\dfrac{75+64}{6}\right)}$

Dividing 6 by 2,

$\longrightarrow\sf{{Perimeter}_{(Rectangle)}=\dfrac{139}{3}}$

$\longrightarrow\sf{{Perimeter}_{(Rectangle)}=46\dfrac{1}{3}}$

❝ Therefore, the Perimeter of rectangular sheet is 46⅓ cm. ❞