a rectangular sheet of paper is 22 cm long and 10 cm wide a cylinder is formed by Rolling the paper along its length find the lateral surface area of the cylinder
Answers
Answered by
30
In the cylinder formed h=22cm and d =10 so r=d/2=10/2= 5 cm
So
LSA of cylinder = 2 × 22 /7×r × h
= 2 × 22/7 × 5 × 22
=
So
LSA of cylinder = 2 × 22 /7×r × h
= 2 × 22/7 × 5 × 22
=
Answered by
33
circumference of base of cylinder=breadth=10cm
=>2πr=10…(1)
height=length=22cm
CSA=2πrh
=10×22(putting (1))
=220cm2
=>2πr=10…(1)
height=length=22cm
CSA=2πrh
=10×22(putting (1))
=220cm2
Similar questions