Question

A rectangular sheet of paper is 54 cm long and 1202 cm wide find its perimeter

Answer 1

Answer:

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Step-by-step explanation:

perimeter=2×(l+b)

=2×(54+1202)

=2512cm

Answer 2

Answer :

›»› The perimeter of a rectangular sheet of paper is 2512 cm.

Diagram :

$\setlength{\unitlength}{26mm}\begin{picture}(4,4)\put(2,1){\line(0,1){1.6}}\put(2,1){\line(1,0){2.5}}\put(4.5,1.0){\line(-,13){1.6}}\put(2,2.6){\line(1,0){2.5}}\put(2.2,1.7){\bf{Perimeter = ?}}\put(2.7,0.6){\bf{l = 54 cm}}\put(1.2,1.9){\bf{}}\put(1.1,1.9){\bf{b = 1202 cm}}\end{picture}$

Given :

• A rectangular sheet of paper is 54 cm long and 1202 cm.

To Find :

• The perimeter of rectangular sheet.

Solution :

$\small\textbf{As we know that}$

⠀

$\footnotesize : \implies \mathscr{P}erimeter = 2(l + b)$

⠀⠀

$\footnotesize : \implies \mathscr{P}erimeter = 2(54 + 1202)$

⠀

$\footnotesize : \implies \mathscr{P}erimeter = 2(1202)$

⠀

$\footnotesize : \implies \bm{\mathscr{P}erimeter = 2512}$

⠀

Hence, The perimeter of a rectangular sheet of paper is 2512 cm.

⠀

⠀⠀⠀⠀⠀⠀⠀$\boxed{ \mid{ \underline{ \overline{ \bf{Extra \: shots}}}\mid}}$

⠀

⠀⋆ Area of Rectangle = length * breadth.

⠀⋆ Perimeter of Rectangle = 2 (l+b).

⠀⋆ Diagonal of Rectangle = √(l)² + (b)².

⠀⋆ Area of Sqaure = Side * Side.

⠀⋆ Perimeter of Square = 4 * Side.

⠀⋆ Diagonal of Square = √2a.