A rectangular sheet of paper is folded about its width 15cm . If the length of the sheet is 22m find the volume of the hollow cylinder thus formed
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Height of cylinder = Width of rectangle.
Height = 15 cm
Circumference of Base of cylinder = Length of rectangle..
=> 2 pi r = 22
=> 2*22*r/7 = 22
=> r = 22*7 / 22*2
=> r = 3.5 cm
Volume = pi *r^2 h
= 22*3.5*3.5*15 / 7
= 22*0.5*3.5*15
= 11*15*3.5
= 577.5 cm^3
Height = 15 cm
Circumference of Base of cylinder = Length of rectangle..
=> 2 pi r = 22
=> 2*22*r/7 = 22
=> r = 22*7 / 22*2
=> r = 3.5 cm
Volume = pi *r^2 h
= 22*3.5*3.5*15 / 7
= 22*0.5*3.5*15
= 11*15*3.5
= 577.5 cm^3
Answered by
2
Hi,
Here is your answer,
{ Height and width }
h =15 cm { Circumference of base of hollow
cylinder = length of rectangular sheet }
→ 2πr = 22
→2 × 22 × /7 = 22
→r = 22 × 7/ 22 × 2 → 154/44 = 3.5
So, radius = 3.5 cm
Volume(V) = π×r²h
→22 × 3.5 × 3.5 × 15 / 7 { Taking 3.5 common}
→ 22 × 0.5 × 3.5 × 15
→11 × 15 × 3.5
→577.5 cm³
Hope it helps you !
Here is your answer,
{ Height and width }
h =15 cm { Circumference of base of hollow
cylinder = length of rectangular sheet }
→ 2πr = 22
→2 × 22 × /7 = 22
→r = 22 × 7/ 22 × 2 → 154/44 = 3.5
So, radius = 3.5 cm
Volume(V) = π×r²h
→22 × 3.5 × 3.5 × 15 / 7 { Taking 3.5 common}
→ 22 × 0.5 × 3.5 × 15
→11 × 15 × 3.5
→577.5 cm³
Hope it helps you !
swapnil756:
Awesome.
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