Question

A rectangular sheet of paper is having measures 11cm *4cm.it is folded without overlapping to make a cylinder of height 4cm . find the volume of the cylinder.

Answer 1

Since height of cylinder=4cm

we are folding sheet about length, its length will be equal to circumference of cylinder.

2 π r = L

2*22*r/7=L

r=11*7/2*22

r=7/4

volume of cylinder=πr²h=(22/7)*(7/4)²*4=38.5 cm³

Answer 2

Answer:

$\small{\boxed{\bold {The\:volume\:of \:cylinder\:is\:38.5cm^3}}}$

$\tt{Given}\begin{cases}\tt{11cm} \\ \tt{4cm} \\\tt{4cm}\end{cases}$

$\large\underline\textsf{To find }$

$\small\textsf{the volume of the cylinder }$

$\large\underline\textsf{Suppose:- }$

$\large\bf{ Radius \:of \:cylinder =\red R}$

$\large\bf{And \:Hieght =\red H}$

$\huge\underline\textsf{Explantion:- }$

$\implies\sf perimeter \: of \: the \: base \: of \: the \: cylinder = 2\pi \: r = 11$

$\implies\sf2 \times \frac{22}{7} \times r = 11$

$\implies\sf r = \frac{7}{4} cm$

$\implies\sf volume \: of \: cylinder = v = \pi \: r {}^{2} h$

$\implies\sf \frac{22}{7} \times \frac{7}{4} \times \frac{7}{4} \times 4cm {}^{3}$

$\leadsto\bf38.5cm {}^{3}$

$\huge\underline\mathfrak\orange{thankyou}$