A rectangular solid block has length 10cm breadth 5cm and height 2 cm. If it has on a horizontal surface and has density 1000kgm-3. Calculate the pressure it exerts on the surface.
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Answered by
0
Answer:
sorry friend I don't know what is the answer of this question
Answered by
0
Answer:
Given that,
density of water (ρ)=10
3
Kg/m
3
water fixed up till height (h)=2 m
Area of base (A)=100 m
2
.
assuming atmospheric pressure (P
0
)=1 atm≃10
5
Pa
so, pressure at bottom of tank,
P=P
0
+ρgh.
=10
5
+10
3
×10×2[g=10 m/s
2
]
P=(1.2×10
5
) Pa
Thus, thrust on bottom surface,
F=P.A=(1.2×10
5
)×10
2
⇒F=1.2×10
7
N
solution
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