a rectangular solid block has sides 4×10×20 cm and a density of 7.5. If it rests on a horizontal flat surface calculate the minimum and maximum pressure it can exert in si units, also calculate thrust in both the cases
Answers
The minimum and maximum pressure a block can exert is 3000 Pa and 15000 Pa and thrust in both the cases is 60N.
Explanation:
Volume Of the given block:
Volume = 4×10×20 cm = 800 cm³
Mass of the block:
mass = volume x density
= 800 * 7.5
= 6000 gm or 6 kg
Weight of the block, W:
W = mg
= 6 * 10
= 60N
But, Thrust = weight { ∵ A block is at equilibrium. thus, net force = 0 }
Therefore, thrust in both the cases = 60N
Pressure exerted by the block:
Pressure (P) = Thrust / face area
=> Maximum pressure:
Pmax = W/Amin = 60/(4x10x10⁻⁴) = 15000 Pa
=> Minimum Pressure:
PMin = W/Amax = 60/(20x10x10⁻⁴) = 3000 Pa
Hence, The minimum and maximum pressure a block can exert is 3000 Pa and 15000 Pa.
Learn more:
Q:1 A block of iron of mass 7.5 kg and of dimensions 12 cm * 8 cm * 10 cm is kept on a table top on its base of side 12 cm * 8 cm. Calculate :
(a) thrust (b) pressure exerted on the table top. Take 1 kgf = 10 N.
Click here : https://brainly.in/question/1061618
Q:2 A cuboid of mass 2 kg and dimensions 3 cm x 5 cm x 20 cm. If g = 10 m/s2 , find the maximum pressure and minimum pressure exerted by this solid on the surface.
Click here : https://brainly.in/question/297856