a rectangular solid has a length of 3 times, the width and the height twice it's width. if, the volume of a rectangular solid is 384 cube inches. determine the dimension of the rectangular solid
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Answer:
let width:x
length is three times of width : 3x
height is twice the width: 2x
volume : 384
so,
L*B*H = 384
x + 3x + 2x = 384
6x = 384
x= 384/6
x=64
Answered by
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Let the width be x
Length = 3 times width = 3x
Height = Twice width = 2x
Volume of rectangle = 384 cube inches
Volume = l*b*h
384 = 3x * x * 2x
384= ( 6x )whole cube
384/6 = x cube
64 = x cube
Root 64 = x
4 = x
:. Length = 3x= 3*4 = 12
Breadth = x = 4
Height = 2x = 2*4 = 8
Length = 3 times width = 3x
Height = Twice width = 2x
Volume of rectangle = 384 cube inches
Volume = l*b*h
384 = 3x * x * 2x
384= ( 6x )whole cube
384/6 = x cube
64 = x cube
Root 64 = x
4 = x
:. Length = 3x= 3*4 = 12
Breadth = x = 4
Height = 2x = 2*4 = 8
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