A rectangular sports field has dimensions 100 m by 42 m. It has two semicircles along
breadth. Find (i) Area of the field. (ii) Perimeter (Length of boundary) of field.
Answers
Answer : 1) Area of Rectangular field = 4200m
2) perimeter of Rectangular field = 284m
Step-by-step explanation:
In a rectangle ABCD,
AB & DC ( length ) = 100m --- (given)
AD & BC ( width ) = 42m -----( given )
Area of Rectangle = length × width
∴ = 100 × 42 ( substituting the given value )
∴ Area of Rectangle = 4200m
Also ,
Perimeter of Rectangle = 2 ( Length + width )
∴ = 2 ( 100 + 42 )
∴ = 2 ( 142 )
∴ Perimeter of Rectangle = 284m
Step-by-step explanation:
area =l×b
perimeter=2(l+b)