Question

a rectangular stall covers an area of 29 3/4 sq.m if the breadth of the stall is 3 1/2m . find its length​

Answer 1

Answer:

8 1/2m

Step-by-step explanation:

Length=area/breadth=119/4/7/2

=17/2=8 1/2m

Answer 2

Answer :-

• The length of the rectangular stall is 8 1/2 m.

To find :-

• The length of the rectangular stall.

Solution :-

• In this question, the breadth and area of a rectangular stall is given to us. We have to find it's length. The stall is in the shape of a rectangle as it's a rectangular stall. So, to find it's length using it's area, we will use the formula required for finding the area of a rectangle.

We know that :-

$\underline{\boxed{\sf Area \: of \: a \: rectangle = Length \times Breadth}}$

Here,

• Area = 29 3/4 sq.m.
• Breadth = 3 1/2 m.

• Let the length of the stall be "l" m.

Substituting the given values in this formula,

$\leadsto \rm 29 \dfrac{3}{4} = l \times 3 \dfrac{1}{2}$

Converting the mixed fractions into improper fractions,

$\leadsto\rm \dfrac{119}{4} = l \times \dfrac{7}{2}$

Multiplying l with 7/2,

$\leadsto\rm \dfrac{119}{4} = \dfrac{7l}{2}$

Transposing 2 from RHS to LHS, changing it's sign,

$\leadsto\rm \dfrac{119}{4} \times 2 = 7l$

Reducing the numbers,

$\leadsto\rm \dfrac{119}{2} \times 1 = 7l$

Multiplying 119/2 with 1,

$\leadsto\rm \dfrac{119}{2} = 7l$

Transposing 7 from RHS to LHS, changing it's sign,

$\leadsto\rm \dfrac{119}{2} \div 7 = l$

The reciprocal of 7 is 1/7, so multiplying 119/2 with 1/7,

$\leadsto\rm \dfrac{119}{2} \times \dfrac{1}{7} = l$

Reducing the numbers,

$\leadsto\rm \dfrac{17}{2} \times \dfrac{1}{1} = l$

Multiplying 17/2 with 1/1,

$\leadsto\rm \dfrac{17}{2} = l$

Converting the improper fraction into mixed fraction,

$\leadsto\overline{\boxed{\rm 8\dfrac{1}{2} \: m= l}}$

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• Hence, the length of the rectangular stall is 8 1/2 m.