A rectangular surface has length 4661 metres and breadth 3318 metres on this area square tiles are to be put find the maximum length of such tiles
Answers
Answered by
11
Answer:
79 meters.
Step-by-step explanation:
This question is testing on the GCD or the HCF.
We need to find the HCF of 4661 and 3318.
We use prime factorization :
3318 = 2 × 3 × 7 × 79
4661 = 59 × 79
From the prime factors the HCF is 79
The squares will be of size 79 meters.
The square tiles will be of side 79 meters by 79 meters.
Answered by
17
Answer:
Max length of tile = 79 m
Step-by-step explanation:
4661 & 3318
Lets find HCF of 4661 & 3318
4661 = 59 * 79
3318 = 2 * 3 * 7 * 79
Common factor is only 79
Sq size of square tile would be 79 * 79 m²
Max length of tile = 79 m
Number of tiles requires = 4661 * 3318 /(79 * 79) = 59 * 42
= 2478
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