A rectangular swimming pool 30 m wide 50 m long and 3 m deep contains 600m3 of water. how much more water has to be added so that the water level is 0.2 from the top?
Answers
Answered by
7
Answer:
2400m3
Step-by-step explanation:
Given : l = 50m
b = 30m
h = 3m
Water in pool = 600m3
600m3 = l × b × h
600m3 = 50 × 30 × h
600 = 1500 × h
h = 600/1500
h = 0.4 m
given, water level is 0.2m from top
therefore, height of water level = 3-0.2
= 2.8m
water to be = volume of water - volume of water
added. of height 2.8m. of height 0.4 m
= (50 × 30 × 2.8) - (50 × 30 × 0.4)
= (2800 - 400 )
= 2400 m3
Answered by
2
Given the side of equilateral triangle is 30 cm
Then area of equilateral triangle=
4
3
(30)
2
=
4
3
×900=225
2
cm
2
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