Math, asked by allyssakho2010, 4 months ago

A rectangular swimming pool 30 m wide 50 m long and 3 m deep contains 600m3 of water. how much more water has to be added so that the water level is 0.2 from the top?

Answers

Answered by gaikwadvedant76
7

Answer:

2400m3

Step-by-step explanation:

Given : l = 50m

b = 30m

h = 3m

Water in pool = 600m3

600m3 = l × b × h

600m3 = 50 × 30 × h

600 = 1500 × h

h = 600/1500

h = 0.4 m

given, water level is 0.2m from top

therefore, height of water level = 3-0.2

= 2.8m

water to be = volume of water - volume of water

added. of height 2.8m. of height 0.4 m

= (50 × 30 × 2.8) - (50 × 30 × 0.4)

= (2800 - 400 )

= 2400 m3

Answered by Anonymous
2

Given the side of equilateral triangle is 30 cm

Then area of equilateral triangle=

4

3

(30)

2

=

4

3

×900=225

2

cm

2

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