Math, asked by elleavery02, 7 months ago

A rectangular swimming pool has length 30m, width 20m and depth 2m. If it is being filled with 10 m^3/min, at what rate is the depth of the water increasing?

Answers

Answered by piyushkumar526
0

Answer:

20 hours: The volume of the pool is (length) × (width) × (height), or 30×10×2=600 cubic meters. Use a standard work equation, RT= W, where W represents the total work of 600 m

3

.

0.5×t=600

t=1200 minutes

Convert this time to hours by dividing by 60: 1200÷60=20 hours.

Alternatively, you could convert first:

hr

0.5m

3

×60min=

hr

30m

3

Next, use the standard work equation:

30 t = 600

t = 20 hours

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