Question

A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a constant 2 feet wide and has an area of 196 square feet. Find the dimensions of the pool.

Answer 1

Answer:

• Length = 30 ft
• Breadth = 15 ft

For full explanation see picture..

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Answer 2

Answer:

Given:- A rectangular swimming pool is twice as long as it is wide

            A small concrete walkway surrounds the pool

            The walkway is a constant 2 feet wide and has an area of 196   square feet

To find:- The dimensions of the pool=?

Step-by-step explanation:      

Let's say the rectangular swimming pool's width is x, and the length is 2x.

The area of the walkway= the area of the outer rectangle - the area of the inner rectangle of outer rectangle  

=$(X+4)*(2X+4)=2x^{2}+12X+16$

area of inner rectangle = $X*2X=2x^{2}$

Area of walkway = $(2x^{2} +12X+16)-(2x^{2} )$

After simplification, you will get

Area of walkway = $12X+6$

Given, area of walkway = 196

12x +16 =196  

12x= 180

divide by 12

x=15 ft.  

Answer: width = 15 ft.; length = 30 ft.