A rectangular swimming pool of length 11 m and breadth 6 m contains water to a uniform depth of 2 m. The pool is emptied in 10 hrs by means of a circular pipe, the radius of its cross section being 10 cm. Calculate in cm/sec the speed of water flowing through the pipe.
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Answer:
1.17 s
Step-by-step explanation:
Volume of water to be flowed out = 11×6×2 m^3
Area of cross-section = πr^2
=22×10/7×100 m^2
Distance covered by water = 11×6×2×7×100/22×10
= 420 m
= 42000 cm
Time taken = 10 hrs
= 36000 s
Speed of water = 42000/36000
= 7/6
= 1.17 cm/s (approx)
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