a rectangular tank 25 cm long and 20 cm wide contains water to a depth of 5 cm. a metal cube of side 8cmis placed in tank so that one face of cube rests at the bottom of tank. find how many litres of wate must be poured in to tank so as to just cover the cube.
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11
Volume of water present in tank = 25 * 20 * 5 =2500cm^3
when a metal cube of side 8cmis placed in tank , then volume of water displaced = 8*8*5=320cm^3
25*20*h=2500*8*8*5
h = 64*5*5
h = 1600cm
now, [(20*25)-(8*8) ]*h=320
(500-64)h=320
h = 320/436
h=0.733
when a metal cube of side 8cmis placed in tank , then volume of water displaced = 8*8*5=320cm^3
25*20*h=2500*8*8*5
h = 64*5*5
h = 1600cm
now, [(20*25)-(8*8) ]*h=320
(500-64)h=320
h = 320/436
h=0.733
MananPadsala8233:
Vol. of cube should be 8×8×8
Answered by
14
Vol. of cuboid (after inserting the cube) = vol of original cuboid + vol of cube.
lbH = lbh + l^3
20×25×H = 20×25×5 + (8×8×8)
H = 6.02 cm
New height after inserting cube = 6.02cm
Water to be added = (height of cube)-(height of water in the cuboid)
Therefore your ans is (8 - 6.02) = 1.98cm
lbH = lbh + l^3
20×25×H = 20×25×5 + (8×8×8)
H = 6.02 cm
New height after inserting cube = 6.02cm
Water to be added = (height of cube)-(height of water in the cuboid)
Therefore your ans is (8 - 6.02) = 1.98cm
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