Question

A rectangular tank 3/2 long, 88 cm wide, contains water to depth of the 65 cm. the water is transferred to an empty tank 2 m long, 1 m wide, find the depth of the water.

Answer 1

$\underline{ \huge \mathfrak{solution}}$
$<b><i> let the depth of water be h cm. then the volume if water in one tank is equal to the volume of water in the other tank.$
therefore,

200 × 100 × h = 150 × 88 × 65

$\implies \: h = \frac{150 \times 88 \times 65}{200 \times 100 }$

$= \huge\bold{42.9} \: cm.$

Answer 2

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