Question

A rectangular tank 5 m X 4.5 m X 2.1 m is dug in the centre of
a rectangular field 13.5 m X 25 m. The earth dug out is evenly
spread over the remaining portion of the field. How much is the
level of the field raised ? ​

Answer 1

Answer:

By the given,

Area of land=13.5×25=33.75 m^2

Volume of the tank=5×4.5×2.1=47.25m^3

Area of tank= 5×4.5=22.5m^2

Remaining land=33.75-22.5=11.25m^2

According to the question the land dug out is spread in the remaining field,

therefore,Volume of tank=Area of remaining × height of raised land

land

47.25=11.25×h

h=4.2m

Answer 2

Answer:4.2 m

Step-by-step explanation: 5*4.5*2.1-13.5*25

47.25-33.75

h=4.2m