Question

A rectangular tank ,5m by 4m and 2m deep, contains water to a depth of 1.5 m . the water in the tank is run off into an empty tank 4m long 3m wide . what will be the depth of the water in the second tank

Answer 1

Volume of 1st tank=(5×4×1.5)m^3=30m^3
Since,Volume of 1st tank=volume of 2nd tank
Therefore,Volume of second tank=30m^3
i.e.4×3×d=30
d=30/4×3=2.5mans

Answer 2

Answer:

$Depth \: of \: second \: tank (d) \\= 2.5\: m$

Step-by-step explanation:

Dimensions of a rectangular tank:

Length (L) = 5m,

Breadth (B) = 4m,

Depth of the water (D) = 1.5 m,

Dimensions of an empty tank :

length (l)= 4m,

breadth (b) = 3m,

Let the depth = d m,

According to the problem given,

If the water in a rectangular tank run off into an empty tank then,

Volume of rectangular tank = Volume of an empty tank

=> L×B×D = l × b × d

$\implies d=\frac{L\times B\times H}{l \times b }\\=\frac{5 \times 4 \times 1.5}{4 \times 3}\\=\frac{30}{12}\: m\\=\frac{5}{2}\\=2.5\:m$

Therefore,.

$Depth \: of \: second \: tank (d) \\= 2.5 \: m$

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