Question

a rectangular tank 6m long, 2 m broad and 2 m deep is full of water. the thrust acting on the bottom of the tank is?

Answer 1

Hey dear here is your answer

Pressure=force/area

Area of base=4×2=8 sq m

We know that the thrust is the reaction force.

and force=weight of the water

weight of the water=mass of water×gravity

mass of water=volume×density of water

volume of water=4 x 2×2=16 cubic metre

density of water=1000kg/m3

mass=volume×density

mass of water=16×1000=16000kg

force=thrust =weight of the water=16000×9.8=156800N
 


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Answer 2

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=> Area of the tank [A] = l × b = 6×2 = 12 m²

=> Volume of tank [V] = l ×b ×h=12×2 =24m³

= 24000 Litre.

=> Acceleration (gravity) = g = 10 m/s²

=> Density of water(D) = 1 kg/l

=> So.. Mass of the tank (m) = D × V = 1×24000 = 24000 kg.

=> Force [F] = m× g = 24000×10 = 24× 10⁴N

=> Thrust = Force/Area = F/A

$\bf = \frac{24}{12} \times {10}^{4} = 2 \times {10}^{4} \: \: pa$
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