Question

A rectangular tank, 8 m deep, is filled with water upto a certain level. If 50% of the water is removed from the tank, the water level falls by 30% of the total depth. Up to what level from the base was the tank filled initially?

Answer 1

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Answer is in the attachment

Answer 2

Question :---- we have to find what level from the base the tank was filled initially....

Given :-----

• Depth of tank = 8m
• 50% of the water removed
• water level falls by = 30% of Total depth .

Let initially water was filled upto height of Xm from base .

Let 1m deep has = 1 litre of water .

so, Total water can we filled in tank = 8 litre .

upto x m height from base it has water = x litre ......

Now it is said that 50% of water removed .

That means water left = (x/2) litre ..

it is also said that water level falls by 30% of total depth

= 8 × 30/100 = 2.4 m

initial height from base = x m

it falls by = 2.4 m

so, new height of water = (x-2.4) m

water now = (x-2.4)*1 = (x - 2.4) litre .

A/q,

(x/2) = (x-2.4)

2.4 = x - (x/2)

x/2 = 2.4

x = 4.8 m (Ans)

so, initially tank was filled 4.8 m high from base ........

(Hope this helps you) ..