a rectangular tank 8m long, 7m wide, and 5 m high, contains water to a depth of 3m. how much more water can it hold
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Answer:
Original capacity of the tank=length ×breadth× height
=(8×7×5) m^3
=280m^3.
Depth at which water is contained in it=3 m
Therefore, the capacity of water which its holding
=(8×7×3)m^3.
= 168 m^3.
Therefore, capacity its holding< capacity it can hold
Amount more it can hold still now=Original capacity -- Capacity its holding.
=280m^3 -- 168 m^3
= 112 m^3.
Required answer. Hope this helps..
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