A rectangular tank is 10 metre long 5 metre broad and perimeter height it is still to the river water of density 10 power 3 kg metre per cube calculate the thrust at the bottom and wall of the tank due to hydrostatic pressure take G is equal to 9.8 metre per second square
Answers
Answered by
0
The total thrust on walls and bottom is 2.793 x 10^6 N
Explanation:
Pressure n the bottom of the tank = ηρg = 3 x 10^3 x 9.8 = 2.94 x 10^3 N/m^2
Area of bottom = Length x breadth = 10 x 5 = 50 mL
Thrust on the bottom = ρ x A = 2.94 x 10^3 x 50 = 1.47 x 10^6 N
Average hydrostatic pressure on the walls.
0 + ηρg / 2 = 1/2 ηρg = 1/2 x 3 x 10^3 x 9.8 = 1.47 x 10^4 N/m^2
Area of broad walls = 2 x l x h = 2 x 10 x 3 = 60 m^2
Area of narrow walls = 2 x b x h = 2 x 5 x 3 = 30 m^2
Thrust on the walls = Average pressure x A = 1.47 x 10^4 x 90
= 1.323 x 10^6 N
Total thrust force on walls and bottom = 1.47 x 10^4 + 1.323 x 10^6 N
= 2.793 x 10^6 N
Hence the total thrust on walls and bottom is 2.793 x 10^6 N
Similar questions