Physics, asked by Ashokkumarapu3805, 8 months ago

A rectangular tank is 10 metre long 5 metre broad and perimeter height it is still to the river water of density 10 power 3 kg metre per cube calculate the thrust at the bottom and wall of the tank due to hydrostatic pressure take G is equal to 9.8 metre per second square

Answers

Answered by Fatimakincsem
0

The total thrust on walls and bottom is 2.793 x 10^6 N

Explanation:

Pressure n the bottom of the tank = ηρg  = 3 x 10^3 x 9.8 = 2.94 x 10^3 N/m^2

Area of bottom = Length x breadth = 10 x 5 = 50 mL

Thrust on the bottom = ρ x A = 2.94 x 10^3 x 50 = 1.47 x 10^6 N

Average hydrostatic pressure on the walls.

0 + ηρg / 2 = 1/2 ηρg = 1/2 x  3 x 10^3 x 9.8 = 1.47 x 10^4 N/m^2

Area of broad walls = 2 x l x h = 2 x 10 x 3 = 60 m^2

Area of narrow walls = 2 x b x h = 2 x 5 x 3 = 30 m^2

Thrust on the walls = Average pressure x A = 1.47 x 10^4 x 90

                                = 1.323 x 10^6 N

Total thrust force on walls and bottom =  1.47 x 10^4 +  1.323 x 10^6 N

                                                                = 2.793 x 10^6 N

Hence the total thrust on walls and bottom is 2.793 x 10^6 N

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