Question

A rectangular tank is 225 m by 162 m at the base. With what speed must water flow into it through and aperture 60 cm by 45 cm that the level may be raised by 20 cm in 5 hours.

plzzzzzzzzz answer it fast and explain this to me!!!!!!!!!!

Answer 1

Cuboid (Tank)
L = 225 m 
B = 162 m
H = 20 cm = 0.2 m

Cuboid (aperture)
b  = 60 cm = 0.6 m 
h = 45 cm = 0.45 m

The length of the aperture = speed * time
⇒s = l / t
here, time = 5 hours = 300 mins

Volume of the tank = volume of water brought by the aperture
lbh = lbh
225*162*0.2 = 0.6 * 0.45 l 
225 * 162 * 2 * 10 * 100 / 10*6*45 = l
⇒ l = 27000 m

speed = 27000 / 300
∴ speed = 90 m/m or 1.5 m/s

Thank You......!!!!!!!!!
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Yours, Jahnavi.

Answer 2

In rectangular tank
L=225m
B=162m
H=20/100
Volume of water flow in tank in 5 hours
v=225*162*20/100
volume of water flow in 1 hour
v=1/5(225*162*20/100)
area of cross section = 60/100*45/100
=27/100m^2


let the flowing speed be x
so, in one hour volume of water in speed is =27/100x
1/5(225*162*20/100) =27/100x
x=5400m/hr