Question

A rectangular tank is 225 mx 162 m at base. With what speed should water flow into it through an aperture 60 cm x 45 cm so that the level of water is raised by 20 cm in 2.5 hours?​

Answer 1

The tank is in the shape of a cuboid.

Volume of a cuboid = l × b × h

Since, after 5 hours, the height of the water is 20cm,

Volume of water in the tank in 5 hours =

225 × 162× 20 / 100 m3 = 7290m3

Let x m/ hour be the speed of the water flowing thought the aperture.

Then, Volume of water flown through the

aperture in 5 hours = (60/100 × 45/100 × 5 × x) m3

Now, 27 x = 7290x = 7290×20

20 ________

27

Total = 5400 m/hr