A rectangular tank of depth 8 meter is full of water (u=4\3), the bottom is seen at the depth X meter ..find the value of x
Answers
Answered by
40
Here you should use the formula,
refractive index of water with respect to air = actual depth/virtual depth.
Given, refractive index of water = 4/3
actual depth = 8m
Virtual depth = X m
∴ 4/3 = 8 /X
⇒X = 8 × 3/4 = 6 m
Hence, answer is X = 6 m
refractive index of water with respect to air = actual depth/virtual depth.
Given, refractive index of water = 4/3
actual depth = 8m
Virtual depth = X m
∴ 4/3 = 8 /X
⇒X = 8 × 3/4 = 6 m
Hence, answer is X = 6 m
Answered by
22
Hello Dear.
Here is the answer---
Given Conditions,
Depth of the Tank = 8 m.
Refractive Index(μ) = 4/3
Apparent Depth = X m.
Using the Formula,
μ = Real Depth/Apparent Depth
4/3 = 8/x
x = (8 × 3)/4
x = 6 m .
Thus, the Depth to which the water will be seen is 6 m.
Hope it helps.
Here is the answer---
Given Conditions,
Depth of the Tank = 8 m.
Refractive Index(μ) = 4/3
Apparent Depth = X m.
Using the Formula,
μ = Real Depth/Apparent Depth
4/3 = 8/x
x = (8 × 3)/4
x = 6 m .
Thus, the Depth to which the water will be seen is 6 m.
Hope it helps.
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