Question

a rectangular that contains two flower beds in the shape of congruent isosceles right triangle the remaining portion is a yard of trapezoidal Shape whose parallel sides of length 15 M and 25 m what fraction of the yard is occupied by the flower bed

Answer 1

AB = DF + FE + EC
25 = 2CF + 15
2CF = 10
DF = EC = 5 m
AD = BC = 5 m
ar(∆) = ½bh
ar(ADF) = ar(BCE) = ½5*5 = 12.5 m²
ar(ABCD) = lb = 5*25 = 125 m²
ar(AFEB) = ar(ABCD) - ar(ADF - ar(BCE) = 125 - 12.5 - 12.5 = 100 m²
total flowerbed area = 2*12.5 = 25 m²
flowerbed area/yard area = 25/100 = ¼
flowerbed area/total area = 25/125 = 1/5