A rectangular tile has dimension 40 cm × 20 cm. If the length and breadth of the tile are increased by 5%, what is the percentage increase in the area of the tile ?
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Answers
Answer:
Area of rectangular tile = 40 cm × 20 cm = 800cm^2
length increased by 5% , then length = 40 + 40 × 5/100 = 42 cm
breadth increased by 5% , then breadth = 20 + 20 × 5/100 = 21 cm
now area of the rectangular tile = 42 cm × 21 cm = 882 cm^2
Increase in the area of tile = 882 cm^2 - 800 cm^2 = 82 cm^2
% increase in area = (82 × 100)/800 = 10.25%
Given:
Dimension of the tile = l x b = 40 cm × 20 cm
Increase in breadth = 5%
To Find:
Percentage increase in the area of the tile
Solution:
Area = 40 x 20
= 800
According to question -
New length = 5% of 40
= 5/100 x 40
= 2
Thus, = 40 + 2 = 42cm
Similarly,
New breadth = 5% of 20
= 5/100 x 20
= 1
Thus, = 20 + 1 = 21
Now,
New area = 42 x 21
= 882 cm sq
% increase in area = [(New tile area - Old tile area) / Old tile area] x 100
= [(882 - 800)/ 800 ] x 100
= 82/800 x 100
= 8200/800
= 10.25
Answer: The percentage increase in the area of the tile is 10.25%