Question

A rectangular tin 20 cm long and 12 cm wide contains 1680 cm³ of flour. what is the depth of flour in the tin if it is spread evenly.​

Answer 1

Volume of the tin= l×b×h

1680cm³= 20cm×12cm×h

h= 1680cm³/240cm²

=140cm/20

=7cm

Therefore, the depth is 7cm

Answer 2

Need To Find :-

• The depth of the flour in the tin ‎. ‎ ‎ ‎ ‎ ‎

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎━━━━━━━━━━━━━━

According to the question, we are given length of a rectangular tin is 20 cm & breadth of the rectangular tin is 12 cm.And finally, volume of flour the rectangular tin contains is 1680 cm³.For solving this question we need to know one formula. Here :-

• Volume of rectangle = l × b × h

Where, l means length of the rectangle, b means breadth of the rectangle and h means height (depth) of the rectangle.So,we just need to put the given values. Let's do it!

Calculation :-

‎

$\implies{\sf{\pmb{Volume \: _{(Rectangle )} =l \times b \times h \:cm³}}}\\ \\ \implies{\sf{1680=20 \times 12 \times h}}\\ \\ \implies{\sf{1680=240 \times h}}\\ \\ \implies{\sf{\dfrac{\cancel{1680}}{\cancel{240}}=h}}\\ \\ \implies\boxed{\tt{\pmb{\red{7\:cm =h}}}}$

$\:$

$\\ \therefore \underline{ \frak { \pmb{The \: depth \: of \: the \: flour \: in \: the \: tin ‎ \: will \: be ‎ \: \purple{7 \: cm }. }}}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

$\large {\boxed{\sf{\mid{\overline {\underline \red {{Know\:More\::}}}\mid}}}}$

• $\sf Area_{(Rectangle)} = Length \times Breadth$

• $\sf Perimeter _{(Rectangle)} = 2 (Length + Breadth)$

• $\sf Area_{(Square)} = Side \times Side$

• $\sf Perimeter _{(Square)} = 4 \times Side$

• $\sf Area_{(Trapezium)} = \dfrac{1}{2} \times Height \times (a + b )$

• $\sf Area_{(Parallelogram)} = Base \times Height$

• $\sf Area_{(Triangle)} = \dfrac{1}{2} \times Base \times Height$

• $\sf Area_{(Rhombus)} = \dfrac{1}{2} \times Diagonal _{1}\times Diagonal_{2}$

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀