Question

A rectangular tin 9 cm long 7cm wide contains 378cm cube of flour. What is the depth of flour in the tin if it is spread evenly?

Answer 1

$\huge\mathbb{SOLUTION:-}$

$\sf\bullet Length\:of\:tin= 9cm\\ \\ \sf\bullet Breadth=7cm\\ \\ \sf\bullet Volume=378cm{}^{3}$

• We have to find the Height of tin

$\underline{\bigstar{\sf{Volume\:of\:cuboid=length\times breadth\times height}}}$

So

$\underline{\dag{\sf{\red{\:\: According\:To\: Question}}}}$

$\sf\implies Volume=l\times b\times h\\ \\ \sf\implies 378=9\times 7\times h\\ \\ \sf\implies 378=63\times h\\ \\ \sf\implies \cancel{\dfrac{378}{63}}=h\\ \\ \sf\implies 6=h\\ \\ \sf\implies \:\:or\:\: Height=6cm$

$\underline{\bigstar{\sf{Depth\:of\:tin=6cm}}}$

Answer 2

AnswEr :

Depth = 6 cm.

$\bf{We\:have}\begin{cases}\sf{Length\:of\:rectangular\:tin\:=\:9\:cm}\\ \sf{Breadth\:(wide)\:of\:rectangular\:tin\:=\:7cm}\\ \sf{Volume\:of\:tine\:or\:capacity=\:378\:cm^{3} }\end{cases}}$

$\bf{\large{\underline{\rm{\red{To\:find\::}}}}}$

The depth (height) of flour in the tin if it's spread evenly.

$\bf{\large{\underline{\underline{\tt{\green{Explanation\::}}}}}}$

We know that formula of the volume of the cuboid :

$\bf{\large{\boxed{\sf{Volume\:of\:cuboid\:=\:Length*breadth*height\:\:\:\:\big(cubic\:unit\big)}}}}}}}$

A/q

$\dashrightarrow\tt{Volume\:=\:lbh}\\\\\\\\\dashrightarrow\tt{378\:cm^{3} \:=\:9cm*7cm*h}\\\\\\\\\dashrightarrow\tt{378\:cm^{3} \:=\:63\;cm^{2} *h}\\\\\\\\\dashrightarrow\tt{h\:=\:\cancel{\dfrac{378cm^{3} }{63cm^{2}} } }\\\\\\\\\dashrightarrow\tt{\red{h\:=\:6\:cm}}$

∴ The depth of flour in the tin is 6 cm.