a rectangular water can is 80 m x 40m x water flows into it through a pipe 40cm2 at the opening speed of 10km/h. by how much the water level will size in the ant 1/2 an hour.
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Opening of a pipe = 40 cm² = 0.004 m²
Speed = 10km/h = 1000m/hr
Volume = 0.004×1000
= 4 m³/hr
Volume filled in ½ hr = 2m³
Volume of cuboid = l×b×h
80×40×h = 2
h = 2/3200
h = 0.000625 m
h = 0.0635 cm
_____________________
hence the water level will rise by 0.0625 cm
Speed = 10km/h = 1000m/hr
Volume = 0.004×1000
= 4 m³/hr
Volume filled in ½ hr = 2m³
Volume of cuboid = l×b×h
80×40×h = 2
h = 2/3200
h = 0.000625 m
h = 0.0635 cm
_____________________
hence the water level will rise by 0.0625 cm
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