Question

A rectangular water reservoir contains 36,000 L of water.Find the depth of the water in the reservoir, if its base measures 8 m by 4 m. Also, find the surface area of the reservoir.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

The height(depth) of the reservoir is 1.125m, and the surface area of the reservoir is 59$m^{2}$.

Step-by-step explanation:

1 $m^{3}$ =1000liters

Given that Volume of the rectangular reservoir = 36000L = 36$m^{3}$

The base of the reservoir measures 8m ×  4m

Therefore, base area = 8 × 4 =32$m^{2}$

now, Depth of reservoir = $\frac{volume}{area of base}$

                                         =$\frac{36}{32} = 1.125m$

Surface area of reservoir = Area of base +Area of 4 sides

                                          =(8 × 4) + 2(1.125 × 4) + 2(1.125 × 8)

                                         =32 + 9 + 18

                                        =59$m^{2}$