Question

a rectangular water reservoir contains 42000 litre of water. Find the depth of the water in the reservoir if its base measure 6m by 3.5m.​

Answer 1

We know that volume of cuboid = length×breadth×height

So, height =Volume/lb

h=V/lb

h=42/(6×3.5)

h=2 m

follow me please

Answer 2

$\large\underline{ \underline{ \sf \maltese{ \: Question:- }}}$

• A rectangular water reservoir contains 42000 litre of water. Find the depth of the water in the reservoir if its base measure 6m by 3.5m.

$\large\underline{ \underline{ \sf \maltese{ \: Given:- }}}$

$\red{\boxed{ \sf \blue{ 1 {m}^{3} \: = \: 1000 \: litres }}}$

• Volume of the Reservoir = $\sf\green{42000\: Litres}$

$\qquad \quad {:} \longrightarrow \sf{\sf{\frac{42000}{1000} \: {m}^{3} }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{\frac{42\cancel{000}}{1\cancel{000}} \: {m}^{3} }}$

$\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{Volume \: of \: Reservoir \: = \: 42 {m}^{3} }}}$

• Length of the Reservoir = $\sf\green{6m}$
• Breadth of Reservoir = $\sf\green{3.5m}$

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$\large\underline{ \underline{ \sf \maltese{ \: Solution:- }}}$

$\begin{gathered}\begin{gathered}\begin{gathered}: \implies \underline\blue{ \boxed{\displaystyle \sf \bold\orange{\: Area \: of \: the \: Base \: of \: the \: Reservoir \: = \: length \: \times \: height }} }\\ \\\end{gathered}\end{gathered}\end{gathered}$

$\qquad \quad {:} \longrightarrow \sf{\sf{area \: = \:( \: 6 \: \times \: 3.5 ) \: {m}^{2} }}$

$\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{ \: Area \:of\: Base= \: 21 {m}^{2} }}}$

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$\begin{gathered}\begin{gathered}\begin{gathered}: \implies \underline\blue{ \boxed{\displaystyle \sf \bold\orange{\: Ar.\: of \: the \: Base \: \times \: Height \: = \: Volume \:of \: Reservoir }} }\\ \\\end{gathered}\end{gathered}\end{gathered}$

$\qquad \quad {:} \longrightarrow \sf{\sf{Height \: or \: Depth \: of \: the \: Reservoir \: = \: \frac{Volume }{Area \: of \: Base } }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{Height \: or \: Depth \: = \: \frac{42}{21} }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{Height \: or \: Depth \: = \: \cancel{\frac{42}{21} } }}$

$\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{ \: Height \: or \: Depth \: = \: 2m }}}$

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$\begin{gathered}\begin{gathered} \therefore\: \sf{ Height \: or \: Depth \: of \: Reservoir \: = \underline {\underline{ 2m}}}\\\end{gathered}\end{gathered}$

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