A rectangular water reservoir is 7.2 m by 2.5 m at the base . Water flows into it through a pipe whose cross-section is 5cm × 3 cm at the rate of 10 m per second . Find the height to which the water will rise in the reservoir in 40 minutes.
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Dimensions of reservoir
Length=7.2m
Breadth=2.5m
Cross sectional area of pipe=(5*3)*10⁻⁴=0.0015m²
Speed of water flow is 10m/s
Time=40min=(40*60)s
Distance water flown in this time=(10*40*60)m
Volume of reservoir=Volume given out by pipe
Let the height be h meters.
24000*0.0015=7.2*2.5*h
h=2 m
Length=7.2m
Breadth=2.5m
Cross sectional area of pipe=(5*3)*10⁻⁴=0.0015m²
Speed of water flow is 10m/s
Time=40min=(40*60)s
Distance water flown in this time=(10*40*60)m
Volume of reservoir=Volume given out by pipe
Let the height be h meters.
24000*0.0015=7.2*2.5*h
h=2 m
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