Math, asked by hotshot4344, 15 hours ago

A rectangular water tank 6m 4m by 5m is half full of water. What volume of water is in the tank.

Answers

Answered by Yuseong
19

Correct Question:

A cuboidal water tank 6m 4m by 5m is half full of water. What volume of water is in the tank?

Answer:

60 m³

Step-by-step explanation:

As per the provided information in the given question, we have :

  • Length of the rectangular tank (l) = 6 m
  • Breadth of the rectangular tank (b) = 4 m
  • Height of the rectangular tank (h) = 5 m
  • The water tank is half full of water.

We have been asked to calculate the volume of water in the tank.

According to the question, the water tank is half full of water, hence :

\longrightarrow\boxed{\sf{Volume_{(Water)} = \dfrac{Volume_{(Tank)}}{2}}}

Now, in order to find the volume of water in the rectangular tank, we'll firstly have to find the volume of the water tank.

\bigstar\;\boxed{\sf{Volume_{(Tank)}= l\times b\times h}}\\

  • l denotes length
  • b denotes breadth
  • h denotes height

On substituting values,

\longrightarrow\sf{Volume_{(Tank)}=(6\times 4 \times 5) \; m^3}\\

\longrightarrow\underline{\boxed{\sf{Volume_{(Tank)}=120 \; m^3}}}\\

Now,

\longrightarrow\boxed{\sf{Volume_{(Water)} = \dfrac{Volume_{(Tank)}}{2}}}

\longrightarrow\sf{Volume_{(Water)} = \dfrac{120\;m^3}{2}}\\

\longrightarrow\underline{\boxed{\sf{Volume_{(Water)}=60 \; m^3}}} \; \; \red{\bigstar}\\

Therefore, the volume of water in the tank is 60 m³.

Answered by Anonymous
12

Appropriate Question :-

A cuboidal water tank 6m by 4m by 5m is half full of water. What volume of water is in the tank ?

As Rectangle is 2-D figure , so not possible to have height and volume

Solution :-

Before starting the question , let's recall how we find the volume of a cuboid , For a cuboid with length , breadth and height l , b and h respectively . Volume is given by ;

 \quad \qquad { \bigstar { \underline { \boxed { \pmb { \bf { \red { \underbrace { Volume \: of \: cuboid \: ( V ) \: = l \times b \times h }}}}}}}}{\bigstar}\quad \qquad

______________________________________

Let us assume that ;

  • length of tank = l = 6 m
  • breadth of tank = b = 4 m
  • height of tank = h = 5 m

Now , Volume of tank :-

 \quad \leadsto \quad \sf V = l \times b \times h

 { : \implies \quad \sf V = 6 \times 4 \times 5 }

 { : \implies \quad \sf V = 24 \times 5 }

 { : \implies \quad \bf V = 120 \: \: m³ }

Since , it is given that the tank is half filled . So ,

 \quad \leadsto \quad \sf Volume \: of \: water \: in \: tank = \dfrac{V}{2}

 { : \implies \quad \sf Volume \: of \: water \: in \: tank = \dfrac{120}{2}}

 { : \implies \quad \sf Volume \: of \: water \: in \: tank = \dfrac{\cancel{120}}{\cancel{2}}}

 { : \implies \quad \bf Volume \: of \: water \: in \: tank = 60 \: m³}

  { \bigstar { \underline { \boxed { \pmb { \bf { \red \therefore {\red { \underbrace  {\: Volume \: of \: water \: in \: tank = 60 \: m³ }}}}}}}}}{\bigstar}\quad \qquad

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