A rectangular wire frame of size 2cm×2cm, is dipped in a soap solution and taken out. a soap film is formed, if the size of the film is changed to 3cm × 3cm, calculate the work done in the process. The surface tension of soap film is 3×10² N/m.
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Answer:
Data A
1
=2×2cm
2
=4×10
−4
m
2
,
A
2
=3×3cm
2
=9×10
−4
m
2
,T=3×10
−2
N/m
As the film has two surfaces, the work done is
W=2T(A
2
−A
1
)=2(3×10
−2
)(9×10
−4
−4×10
−4
)=3.0×10
−5
=30μJ.
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